express the trigonometric ratios sin A,secA, tan A ,in terms of cot A
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Hey there !
Solution:
Sin A in terms of Cot A
=> Cot A = Cos A / Sin A
=> Sin A = Cos A / Cot A
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Sec A in terms of Cot A
=> Cot A = Cos A / Sin A
=> Cot A = Cos A . Cosec A
=> Cot A = Cosec A / Sec A
=> Sec A = Cosec A . Cot A
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Tan A = Sin A / Cos A
Reciprocating on both sides we get,
=> 1 / Tan A = Cos A / Sin A
=> 1 / Tan A = Cot A
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Hope my answer helped !
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