Question

express the trigonometric ratios sin A 'secAand tan A in terms of cot A.​

Answer 1

Answer:

Step-by-step explanation:

we know that,

sin²A+cos²A=1

and,1+cot²A=cosec²A

∴cot²A=cosec²A-1

 cot²A=1/sin²A-1                          (∵cosecA=1/sinA)

 cot²A=1-sin²A/sin²A

cotA=√(1-sin²A/sin²A)

       

now A/Q

sinA=1/√1+cot²A

secA=√1+cot²A/cotA

tanA=1/cotA

i hope this will helpful for U

PLZ MARK ME AS BRAINLIST.