Question

Express the trigonometric ratios sinA, secA, and tanA in terms of cotA.
plz solve​

Answer 1

tan A =1/ cot A

cosec²A-cot²A =1

cosec²A=1-cot²A

cosecA =√1-cot²A

1/sinA=√1-cot²A

sin A=1/√1-cot²A

sec²A-tan²A=1

secA =√1-tan²A

=√cot²A-1/cot ²A