Math, asked by nandanadileesh, 1 year ago

Express the trigonometric ratios sinA, secA, and tanA in terms of cotA.

Answers

Answered by Quicksilver007
9

Answer: Sent below ............. Hope it helps


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Answered by Anonymous
8

Answer:

Step-by-step explanation:

cosec²A-cot²A=1

cosec²A=1+cot²A

cosecA=√1+cot²A

1/sinA=√1+cot²A

∵sinA=1/√cot²A

sec²A-tan²A=1

sec²A=1+tan²A

sec²A=1+1/cot²A

sec²A=cot²A+1/cot²A

∵secA=√cot²A+1/cot²A

Please mark it as brainlist answer

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