Express the trigonometric ratios sinA, secA, and tanA in terms of cotA.
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Answer: Sent below ............. Hope it helps
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nandanadileesh:
Thanku...
Answered by
8
Answer:
Step-by-step explanation:
cosec²A-cot²A=1
cosec²A=1+cot²A
cosecA=√1+cot²A
1/sinA=√1+cot²A
∵sinA=1/√cot²A
sec²A-tan²A=1
sec²A=1+tan²A
sec²A=1+1/cot²A
sec²A=cot²A+1/cot²A
∵secA=√cot²A+1/cot²A
∴Please mark it as brainlist answer
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