Express the trigonometry ratios sin A, secA and tanA in term of cot A
Answers
Answered by
2
sinA=tanA*cosA==COSA/COTA
SECA=√(1-TAN^2A)=√(1-1/COT^2A)
TANA=1/COTA ANSWER
SECA=√(1-TAN^2A)=√(1-1/COT^2A)
TANA=1/COTA ANSWER
Similar questions