EXPRESS THE TRIGONOMETRY RATIOS sinA,secA, and tanAin term of cotA .
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Answered by
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HELLO DEAR,
we know that:-
cosec²A=1+cot²A
=>cosec²A=√(1+cot ²A)-------(1)
and
sinA=1/cosecA
sinA=1/√(1+cot²A)-----using (1)
secA
we know that:-
1+tan ²A=sec²A
secA=√{1+ 1/cot ²A}
=>√(cot ²A+1)/cotA
tanA
we know that:-
tan A=1/cot A
I HOPE ITS HELP YOU DEAR,
THANKS
we know that:-
cosec²A=1+cot²A
=>cosec²A=√(1+cot ²A)-------(1)
and
sinA=1/cosecA
sinA=1/√(1+cot²A)-----using (1)
secA
we know that:-
1+tan ²A=sec²A
secA=√{1+ 1/cot ²A}
=>√(cot ²A+1)/cotA
tanA
we know that:-
tan A=1/cot A
I HOPE ITS HELP YOU DEAR,
THANKS
rohitkumargupta:
itna hard questions karte ho
Answered by
3
hope it will help you ...
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