Express this in a+ib form (1 - i )4
Answers
Answered by
5
Hi
here is your answer ,
★ complex number ★
Q. Express this in a + ib from ( 1 - i )⁴
Answer:-
_______
( 1 - i )⁴
= { ( 1 - i )² }²
= { ( 1² - 2.1.( i ) + i² }² [ °.° ( a - b )² = a² - 2ab + b² ]
= ( 1 - 2i - 1 )² [ we know that , i² = - 1 ]
= ( - 2i )²
= 4i²
= -4
so
-4 + i.0 is the answer , where
a = - 4
b = 0
hopes I helped
===================================
here is your answer ,
★ complex number ★
Q. Express this in a + ib from ( 1 - i )⁴
Answer:-
_______
( 1 - i )⁴
= { ( 1 - i )² }²
= { ( 1² - 2.1.( i ) + i² }² [ °.° ( a - b )² = a² - 2ab + b² ]
= ( 1 - 2i - 1 )² [ we know that , i² = - 1 ]
= ( - 2i )²
= 4i²
= -4
so
-4 + i.0 is the answer , where
a = - 4
b = 0
hopes I helped
===================================
Sufiyan111:
No that 4 on ( 1 - i)^4
Answered by
4
hey there
here is your ans ..
◆◆◆◆◆◆◆◆
hope its correct
●●●●●●●●●●●●
(1-i)^4
{(1-i)^2}^2
{(1+i^2-2i)}^2
{(1-1-2i)}^2
(-2i)^2
4i^2
(-4)=-4+0i
where a=-4 and b=0
>>this is in the form of a+ib where
a is equal to-4
●●and●●
b is equal to 0
◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆
◆◆◆◆◆◆◆◆◆
◆◆◆◆
◆◆
here is your ans ..
◆◆◆◆◆◆◆◆
hope its correct
●●●●●●●●●●●●
(1-i)^4
{(1-i)^2}^2
{(1+i^2-2i)}^2
{(1-1-2i)}^2
(-2i)^2
4i^2
(-4)=-4+0i
where a=-4 and b=0
>>this is in the form of a+ib where
a is equal to-4
●●and●●
b is equal to 0
◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆
◆◆◆◆◆◆◆◆◆
◆◆◆◆
◆◆
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