Express this in a+ib form (1 - i)^4
Answers
Answered by
53
hey there
here is your ans ..
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hope its correct
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(1-i)^4
{(1-i)^2}^2
{(1+i^2-2i)}^2
{(1-1-2i)}^2
(-2i)^2
4i^2
(-4)=-4+0i
where a=-4 and b=0
>>this is in the form of a+ib where
a is equal to-4
●●and●●
b is equal to 0
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◆◆◆◆◆◆◆◆◆
◆◆◆◆
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here is your ans ..
◆◆◆◆◆◆◆◆
hope its correct
●●●●●●●●●●●●
(1-i)^4
{(1-i)^2}^2
{(1+i^2-2i)}^2
{(1-1-2i)}^2
(-2i)^2
4i^2
(-4)=-4+0i
where a=-4 and b=0
>>this is in the form of a+ib where
a is equal to-4
●●and●●
b is equal to 0
◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆
◆◆◆◆◆◆◆◆◆
◆◆◆◆
◆◆
Answered by
125
Hi
here is your answer
★ complex number ★
Q. Express this in a + ib from ( 1 - i )⁴
Answer:-
_______
( 1 - i )⁴
= { ( 1 - i )² }²
= { ( 1 )² - 2.1.( i ) + ( i )²}² [ °.° ( a - b )² = a² - 2ab + b² ]
= ( 1 - 2i - 1 )² [ we know that i ² = -1
= ( - 2i )²
= 4i²
= - 4
so
-4 + i.0 is the answer, where
a = -4
b= 0
Hopes I helped you
thanks
# I am a Useless user .
here is your answer
★ complex number ★
Q. Express this in a + ib from ( 1 - i )⁴
Answer:-
_______
( 1 - i )⁴
= { ( 1 - i )² }²
= { ( 1 )² - 2.1.( i ) + ( i )²}² [ °.° ( a - b )² = a² - 2ab + b² ]
= ( 1 - 2i - 1 )² [ we know that i ² = -1
= ( - 2i )²
= 4i²
= - 4
so
-4 + i.0 is the answer, where
a = -4
b= 0
Hopes I helped you
thanks
# I am a Useless user .
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