Question

Express this sum or difference as a single logarithm​

Answer 1

Answer:

Logarithmic Identities:

• log a + log b = log ( ab )
• log c - log d = log ( c/d )

Here both the bases must be having the same value.

According to the question,

⇒ log₂ 12 - log₂ 2 + log₂ 5 = Single Logarithm

⇒ log₂ ( 12/2 ) + log₂ 5

⇒ log₂ 6 + log₂ 5

⇒ log₂ ( 6 × 5 )

⇒ log₂ 30

Therefore the value of  log₂ 12 - log₂ 2 + log₂ 5 as a single logarithm is log₂ 30

Answer 2

Solutions:

$log_{2}(12 \div 2) + log_{2}(5) \\ log_{2}(6) + log_{2}(5) \\ log_{2}(6 \times 5) log_{}(30)$

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