express trignometric ratio of secA and tanA in terms of sinA
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Answered by
5
SecA=1/cosA
But cos^2A=1-sin^2
So cosA=√1-sin^2
Then
SecA=1/1-sin^2
And
TanA=sinA/cosA
TanA=sinA/√1-sin^2
But cos^2A=1-sin^2
So cosA=√1-sin^2
Then
SecA=1/1-sin^2
And
TanA=sinA/cosA
TanA=sinA/√1-sin^2
sakura2121:
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hmm
put a after sin^2
Answered by
2
Answer:secA=1/cosA
CosA = √1-sin^2A
SecA=1/ √1-sin^2A
TanA=sinA/cosA
= SinA/ √1-sin^2A.
I hope this helps you.
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