Question

express trignometric ratio of secA and tanA in terms of sinA

Answer 1

SecA=1/cosA

But cos^2A=1-sin^2
So cosA=√1-sin^2
Then
SecA=1/1-sin^2

And
TanA=sinA/cosA
TanA=sinA/√1-sin^2

Answer 2

Answer:secA=1/cosA

CosA = √1-sin^2A

SecA=1/ √1-sin^2A

TanA=sinA/cosA

= SinA/ √1-sin^2A.

I hope this helps you.

Please mark it as brainliest answer

Step-by-step explanation: