express trigonometric ratios of sec A and tan A in terms of sin A
Answers
Answered by
22
sec A=1/cos A
tan A=sin A/cos A.
tan A=sin A/cos A.
Answered by
73
Answer:
secA=1/cosA
secA=1/sin(90-A)
tanA=sinA/cosA
cosA=sin(90-A)
so,
tanA=sinA/sin(90-A)
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