Math, asked by darsh1284, 1 year ago

express trigonometric ratios of sec A and tan A in terms of sin A

Answers

Answered by 1Siddharth1
22
sec A=1/cos A
tan A=sin A/cos A.
Answered by ayushsingh10711
73

Answer:

secA=1/cosA

secA=1/sin(90-A)

tanA=sinA/cosA

cosA=sin(90-A)

so,

tanA=sinA/sin(90-A)

Similar questions