express trigonometric ratios of sec A and tan A in terms of Sin A
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Anonymous:
Nice solution. Watch the signs though as every one of the square root signs really could be "plus or minus the square root of ...". (E.g. as it stands, sec A would never be negative, but sometimes it _is_.)
Ok.but in trigonometric identities ,most of the times the signs are ignored.
you tanA prove is wrong it is sinA/CosA
Well spotted! That bit needs to flipped over!
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the above given answer is right
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