Express with rational denominator 1/ 1+√6-√7
Answers
Answered by
0
Step-by-step explanation:
1/ ( 1 + √2 - √3 )
= ( 1 +√2+√3)/[(1+√2-√3)(1+√2+√3)]
= (1+√2+√3)/[(1+√2)² - (√3)² ]
= ( 1+√2+√3)/[ 1+2+2√2-3 ]
= ( 1+√2+√3)/ ( 2√2)
= [ √2(1 + √2 + √3 )]/( 2√2 × √2 )
= ( √2 + 2 + √6 ) / 4
I hope this helps you.
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Answered by
7
Answer: hello, here is your answer
√6(1+√6+√7)
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12
Step-by-step explanation:
1
soln: _____________
1+√6-√7
= 1 { (1+√6)+√7}
______________
{(1+√6)-√7} {1+√6)+√7}
= 1+√6+√7
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(1+√6)²+√7²
=. 1+√6+√7
_____________
(1+√6)+√7²
=. 1+√6+√7
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(1+√6)+√7²
=. 1+√6+√7
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1²+21√6+√6²-√7²
=. 1+√6+√7
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1+2√6+6-√7
=. 1+√6+√7
______________
2√6
=. (1+√6+√7)√6
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2√6.√6
=. √6(1+√6+√7)
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2×6
=. √6(1+√6+√7)
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12
=. 6+√6+√42
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12
Final answer hope its help you
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