Express x^2+12x+11 in the form (x+p)^2+q A curve has equation y=x^2+12x+11 What are the coordinates of the turning point of the curve
Answers
Answer: Answer for a) = (x+6)^2-25
b)(-6,-25)
Step-by-step explanation:
a) The goal of this whole equation is to make it into a repeating squared one, therefore we are going to take two numbers that when add together form a 12 thus the only option we have is six. (x+6)^2. Then we need to add the variable "q". so we expand (x+6)^2 and we get x^2+12x+36. Now we compare x^2+12x+36 to x^2+12x+11. Our goal now is to subtract 36 from 11. Therefore we get -25. We get our final component. Now we just assemble the equation and we get (x+6)^2-25. If you want to check it we can expand it and we will get x^2+12x+11.
b)For be I plotted a graph by making a table, I inputted values from -10 to 10 and implemented it in the equation when i saw the turning point i just wrote it down and it happened to be -6,-25.