Express x in term of y given that 3x+4y=6 check whether the point (3,2)
Is on the line
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Solution:
i ) Given 3x+4y = 6
=> 3x = -4y + 6
Divide each term by 3 , we get
=> x = (-4/3)y + 2 ----(1)
ii ) Substitute (3,2) in the equation 3x+4y=6, we get
3×3+4×2 = 6
=> 9 +8 = 6
=> 17 = 6 [ False ]
Therefore,
(3,2 ) point doesn't lie on the
given line .
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