Question

express x in the term of y for x\6+3y=7​

Answer 1

Explanation:

Now, to check whether (1,2) will lie on the line 3x−2y=6, we have to put the value of (x,y) in the given equation.

LHS =3(1)−2(2)=3−4=−1

=6 or RHS

Therefore, the point (1,2) will not lie on the line 3x−2y=6.

Now, at x=4, we have,

3(4)−2y=6

y=3

Again, 3x−2y=6

⇒ At x=0,y=−3 and at y=0,x=2

Therefore, table of points is:

x 0 2

y −3 0

So, graph of the given line is as:

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