Express x in the terms of y in 3x+4y=6 check whether the point (3, 2) is a solution of the equation
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Given, equation: $$3x - 2y = 6$$.
Now, to check whether (1,2) will lie on the line 3x−2y=6, we have to put the value of (x,y) in the given equation.
LHS =3(1)−2(2)=3−4=−1 =6 or RHS
Therefore, the point (1,2) will not lie on the line 3x−2y=6.
Now, at x=4, we have,
3(4)−2y=6
y=3
Again, 3x−2y=6
⇒ At x=0,y=−3 and at y=0,x=2
Therefore, table of points is:
x 02y −3 0
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