Question

Express {(x, y) / x² + y² = 100, where x, y ∈ W} as a set of ordered pairs.

Answer 1

Answer:

{(0, 10), (6, 8), (8, 6), (10, 0)}

Step-by-step explanation:

Hi,

Given that {(x, y) / x² + y² = 100, where x, y ∈ W}

Since x, y ∈ W

Let x = 0 , then y² = 100

⇒ y = ± 10

But y ∈ W, so y = 10

Hence (0, 10) is an ordered pair.

Let x = 1

⇒ 1² + y² = 100

⇒ y² = 99

⇒ y = ±√99 ∉W

So on continuing for each value of x , we observe that for x = 6

6² + y² = 100,

⇒ y² = 100 - 36 = 64

⇒ y = ± 8 but -8∉W, hence y = 8

So, (6, 8) is an ordered pair

Similarly (8, 6)  and (10, 0) are also ordered pair by interchanging

x and y values, and also there are no other ordered pairs such

that both x, y ∈ W and x² + y² = 100.

Hence, the only ordered pairs are {(0, 10), (6, 8), (8, 6), (10, 0)}

Hope, it helps !

Answer 2

Answer:

jai shree ram upar answer diya hua h