express y in terms of x in the equation 2x + 3y = 11, also find the point where the line represented by the equation 2x + 3y = 11 cuts the y axis. Explain with graph.
Answers
Answer:
2x+3y=11
3y=11-2x
y=(11-2x)/3
when-x=1,y=3
when -x=2,y=5
when-x=4,y=1
Step-by-step explanation:
hope this helps
Answer:
- y = -2/3x + 11/3
- The line cuts y axis at 11/3
Step-by-step explanation:
Given equation of straight line is 2x + 3y = 11.
We have to express y in terms of x and have to find the y intercept ( i.e. the point on y axis where the graph crosses the y axis ).
Solution:
By given equation, we have:
=> 2x + 3y = 11
=> 3y = 11 - 2x
=> y = (11 - 2x)/3
=> y = 11/3 - 2/3x
=> y = -2/3x + 11/3
This is the required equation where y is expressed in terms of x.
Here, this is the slope intercept form of straight line which is given by, y = mx + c. Here, m = Slope of line and c is the y intercept.
By comparing this general form of equation of straight line with our original equation, we get :
c = 11/3
Therefore, y intercept = 11/3
Refer to the attachment for graph.
