Question

Express y in terms of x in the equation 2x–3y=12.find the points where the line represented by this equation cuts x axis and y axis. URGENT

Answer 1

Answer:

Given:

• Express y in terms of x in the equation 2x – 3y = 12.

Find:

• Find the points where the line represented by this equation cuts x axis and y axis.

Calculations:

⇢ 2x - 3y = 12

⇢ 2x - 12 = 3y

⇢ y = 2/3x - 4

Adding y = 0 in the given equation, we get:

⇢ 2x - 3(0) = 12

⇢ 2x - 0 = 12

⇢ x = 6

Therefore, value of x in the equation is 6.

Adding x = 0 in the given equation, we get:

⇢ 2(0) - 3y = 12

⇢ 0 - 3y = 12

⇢ -3y = 12

⇢ y = -4

Therefore, value of y in the equation is -4.

Therefore, (6 , 0) and (0, -4) are the two points which cuts x-axis and y-axis.

Note:

• Refer the graph in the attachment.

Answer 2

Answer:

Step 1:  

Given equation is 2x-3y=12

Lines cuts by both x-axis and y –axis

Step 2:

y can be expressed in terms of x as,

2x-3y=12

=2x-12=3y

y=  2/3x-4

Step 3:

the points where this line cuts the x-axis and y-axis can be found as,

put y=0 in 2x-3y=12

=2x-3(0)=12

2x-0=12

X=6

Step 4:

Put x=0 in 2x-3y=12

Then 2(0)-3y=12

0-3y=12

-3y=12

Y= -4

Result:

Thus the points of both x-axis and y axis is (6,0) and  (0,-4)