Question

Express y in terms of x in the equations 2x +3y=11 also find the point where the line represented by equation 2x +3y=11 cuts the y axis

Answer 1

2x +3y= 11
3y= 11-2x
y= (11-2x)/3

when x=1, y=3
when x=-2, y=5
when x=4, y=1

x 1 -2 4
y 3 5 1

sorry, no graphs. hope this much helps.

Answer 2

Answer:

Required point is

$(0, \frac{11}{3} )$

Step-by-step explanation:

Given equation,

$2x + 3y = 11$.........(i)

Dividing both side by 3 and get

$\frac{2x}{3} + y = \frac{11}{3}$

Now,

$y = \frac{11}{3} - \frac{2x}{3} = \frac{11 - 2x}{3}$

Now given the given line cuts the y axis.

Let co-ordinate of any point be (x,y)

if it is lies on y-axis then x=0,

For example (0.2),(0,6),(0.9) all are lies in y-axis.

Now we putting x=0 in equation (i) and get,

$2 \times 0 + 3y = 11$

$0 + 3y = 11$

$y = \frac{11}{3}$

So points on y-axis is

$( 0, \frac{11}{3} )$