express y in the terms of x in equation 2x-3y=12.find the points where the lines represent by the equation cuts x-axis and y-axis
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3y = 2x-12
y = (2x-12)/3
when x=0, y= -4
when x=3, y=-2
when x=-3, y=-6
x 0 3 -3
y -4 -2 -6
sorry, i can't post the graph. hope this helps.
y = (2x-12)/3
when x=0, y= -4
when x=3, y=-2
when x=-3, y=-6
x 0 3 -3
y -4 -2 -6
sorry, i can't post the graph. hope this helps.
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