Question

. Express z= -√3+ i in polar form​

Answer 1

Answer:

  = 2 ( cos $\frac{pie}{6}$  + i sin $\frac{pie}{6}$ ) , is the required answer

Step-by-step explanation:

So we have , z = -√3+ i and therefore r = |z| = $\sqrt{-(\sqrt{3}) ^{2} + 1^{2} }$  = $\sqrt{4} = 2$

argument = $\frac{b}{a} = \frac{1}{-\sqrt{3} }$ as it will be always positive so it be $tan^{-1} (\frac{1}{\sqrt{3} } )$ = $\frac{pie}{6}$

therefore polar form = r ( cos thita + i sin thita )

                                  = 2 ( cos $\frac{pie}{6}$  + i sin $\frac{pie}{6}$ ) , is the required answer