Expression for electric field intensity due to pt. Charge
Answers
Answered by
0
Answer:
Electric field due to point charge = kq/r²
Explanation:
We know that,
F = qE that is,
Force = Charge × Electric field
Therefore,
Electric field = Force / Charge
We know that,
Force = 1 / 4πε₀ q₁q₂/r²
Force = k q₁q₂/r²
Hence the field due to q₁ at q₂ will be,
Electric field = Force / Charge
Electric field = 1 / 4πε₀ q₁q₂/r² * 1/q₂
= k q₁q₂/r² * 1/q₂
= kq₁ / r²
= kq / r²
Similar questions
Biology,
4 months ago
English,
4 months ago
CBSE BOARD X,
4 months ago
Psychology,
8 months ago
Math,
8 months ago
History,
11 months ago
Math,
11 months ago
English,
11 months ago