Question

expression for kinetic energy

Answer 1

k.E=1/2mv2 this is answer

Answer 2

$\Large{\underline{\underline{\bf{Anwer:-}}}}$

Expression for Kinetic energy

Consideration:-

Consider an object of mass 'm' by applying force 'F' on it . Acceleration 'a' is produced in the object.This object will be displaced through distance 'S' due to this applied force.

Proof:-

$F = ma$

➥By using third equation of motion

$2as = v^2 - u^2$

➥object initially at rest

$u=0m/s$

$⟹2as = {v}^{2} - {u}^{2} \\ \\ ⟹a = \frac{ {v}^{2} }{2s}$

➥Putting value of 'a' in 2as = v² - u²

$f = \frac{1}{2} m \times \frac{ {v}^{2} }{s}$

Now,

$W = FS$

$⟹w = \frac{1}{2} m \times \frac{ {v}^{2} }{s} \times s \\ \\ ⟹w = \frac{1}{2} m {v}^{2}$

➥This work done will be stored in the form of Kinetic energy in this object.

$\Large{\underline{\underline{\bf{Thanks}}}}$