EXPUNENTAL
DISTRIBUTI
9-59. Suppose that during rainy season on a tropical island the length of the shower has an exponential distribution, with parameter λ = 2, time being measured in minutes. What is the probability that a shower will last more than three minutes ? If a shower has already lasted for 2 minutes, what is the probability that it will last for at least one more minute ?
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Answer:
P(X > 3min) = 0.002478
P( X >= 3 / X = 2) = 0.135335
Step-by-step explanation:
X has an exponential distribution with parameter λ = 2
pdf of X => f(x) = λe^(-λx) = 2e^(-2x)
cdf of X => F(x) = 1- e^(-λx) = 1-e^(-2x)
P(X > 3) = 1 - F(3) = e^(-(2 * 3)) = e^(-6) = 0.002478
P( X >=3 / X=2) = P( X >= 1) => Lack of memory property
P(X >= 1) = 1 - F(1) = e^(-2) = 0.135335
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