Exterior angle 70 degree opposite angle 3:4 find angle of triangle
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let the angles of the triangle be, 3x and 4x.
angle ACB + exterior angle ACB (linear pair)
180 = angle ACB + 70
180-70= angle ACB
110= angle ACB
With angle sum property of triangle
angle ABC +angle ACB+ angleBAC = 180
4X+ 3X+110=180
7X=180-110
7X=70
X=70/7
X=10
3X=30
4X=40
ALL THE ANGLES ARE 110, 30,40
angle ACB + exterior angle ACB (linear pair)
180 = angle ACB + 70
180-70= angle ACB
110= angle ACB
With angle sum property of triangle
angle ABC +angle ACB+ angleBAC = 180
4X+ 3X+110=180
7X=180-110
7X=70
X=70/7
X=10
3X=30
4X=40
ALL THE ANGLES ARE 110, 30,40
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