Question

exterior angle ∆ ACD of a triangle is 100 degree and ∆ ABC and ∆BAC are in the ratio
of 2:3 , find all the angle of the triangle . ​

Answer 1

Answer:

angle sum property of triangle

angle A + angleB +angle C = 180

2x +3x + 80 = 180

5x= 100 = x = 20

now,

2x = 2 *20 =40

3x= 3*20 = 60

Answer 2

Answer:

∠ ABC- 40

∠BAC-60

∠ACB- 80

Step-by-step explanation:

∠ACB+∠ACD= 180 (linear pair)

∠ACB= 180-100

∠ACB=80

Exterior angle theorem: Exterior angle of a triangle is equal to the sum of opposite and non-adjacent interior angles

So ∠ABC + ∠BAC = 100

Ratio= 2:3 = 2x:3x

2x+3x= 100

= 5x=100

x= 100/5=20

2x= 2*20: 3x= 3*20

= 40:60