Physics, asked by Himanshu202866, 3 months ago

External and internal diameters of a hollow cylinder are measured to be (4.23±0.01) cm and (3.89±0.01) cm. The thickness of the wall of the cylinder is​

Answers

Answered by DipakDamor
0

Answer:

0.17+-0.1

Explanation:

As radius =Diameter/2

using this equation

  • Now thicknes=externaldiameter-intern Diameter/2
  • therefore 4.23-3 .89/2
  • =0.34/2
  • =0.17 + or - 0.01
Answered by vaishanvi101
1

The external and internal diameters of a hollow cylinder are measured to be (4.23 ± 0.01) cm and (3.89 ± 0.01)cm. The thickness of the wall of the cylinder is. (0.34±0.02)cm.

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