External and internal diameters of a hollow cylinder are measured to be (4.23±0.01) cm and (3.89±0.01) cm. The thickness of the wall of the cylinder is
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Answer:
0.17+-0.1
Explanation:
As radius =Diameter/2
using this equation
- Now thicknes=externaldiameter-intern Diameter/2
- therefore 4.23-3 .89/2
- =0.34/2
- =0.17 + or - 0.01
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The external and internal diameters of a hollow cylinder are measured to be (4.23 ± 0.01) cm and (3.89 ± 0.01)cm. The thickness of the wall of the cylinder is. (0.34±0.02)cm.
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