external diameter of pipe is 25 cm and length 20 cm thickness is 1 cm find its tsa
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The diameter of the base is D=25cm hence the radius is R=12.5cm
The radius of the circle base is r = R – thickness = 12.5–1=11.5cm
The height is h=20cm
The whole Surface Area of the pipe =2πRh+2πrh+2π(R2−r2)=2⋅3.14⋅12.5⋅20+2⋅3.14⋅11.5⋅20+2⋅3.14(12.52−11.52)=1570+1444.44+6.28(156.25–132.25)=3014.4+148.8=3163.2cm2
The radius of the circle base is r = R – thickness = 12.5–1=11.5cm
The height is h=20cm
The whole Surface Area of the pipe =2πRh+2πrh+2π(R2−r2)=2⋅3.14⋅12.5⋅20+2⋅3.14⋅11.5⋅20+2⋅3.14(12.52−11.52)=1570+1444.44+6.28(156.25–132.25)=3014.4+148.8=3163.2cm2
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