Question

external point.
30. ABCD is the diameter of circle of radius
6cm. The lengths AB, BC and CD are
equal. Semicircles are drawn on AB and
BD as diameters. Find the perimeter and
the Area of the shaded region.​

Answer 1

Answer:

question is not clear, please write again

Answer 2

Answer:

ANSWER

Since, Length of AB, BC and CD are equal.

Radius of circle =6cm

Now, AD=2×6=12cm

⇒AB+BC+CD=12

⇒3AB=12

⇒AB=  12/3

⇒AB=4cm

⇒AB=BC=CD=4cm

Radius of semicircle AB=2cm

Radius of semicircle BC=4cm

Radius of semicircle AD=6cm

Area of the shaded region = Area of semicircle (AB+AD) − Area of semicircle (BD)

⇒ Area of shaded region =0.5π(2² +6²)−0.5π(4)²

⇒ Area of shaded region =0.6π(4+36)−0.5π×16

⇒ Area of shaded region =20π−8π

⇒ Area of shaded region =12πcm²