Question

External radius of a 5m long hollow copper tube is 1.4 cm and it's thickness is 3.5mm. If resistivity of copper be 1.62, then find the resistance of the tube.​

Answer 1

Answer:

R= Resistance of the wire

p= specific resistance

l=length of the wire

a= area of cross section of the wire

With the given values,

A= 1.96349541*10^-7

p = 1.6*10^-8

R= 10

l=(10*1.96349541*10^-7) /(1.6*10^-8)

l=122.7m