Chemistry, asked by desaiutsav23, 1 month ago

Extinction coefficient of NADH at 340 nm is 6440 L/mol/cm. What absorbance will be observed when light at 340 nm passes through a 1 cm cuvette containing 10 UM NADH.​

Answers

Answered by Anonymous
0

Answer:

A string of length 0.4 m and mass 10

−2

is tightly clamped at its ends. The tension in the string is 1.6 N. Identical wave pulses are produced at one end at equal intervals of time, △t. The minimum value of △t which allows constructive interference between successive pulses is

Answered by anjali13lm
0

Answer:

Absorbance observed when the light at 340 nm passes through 1 cm cuvette is 6.44 × 10⁻²

Explanation:

Given,

The molar extinction coefficient of NADH at 340 nm, ε = 6440 L mol⁻¹ cm⁻¹ = 6440 M ⁻¹ cm⁻¹

The concentration of solution, C = 10 μM

Convert μM into M

  • 1 μM = 10⁻⁶ M
  • 10 μM = 10 × 10⁻⁶M = 10⁻⁵ M

Path length, L = 1 cm

Absorbance is observed when light passes through a cuvette at 340 nm,

A =?

As we know,

  • Beer-Lambert's law determines the relationship between the concentration and the absorbance of the solution.
  • It states that the concentration and path length of the sample is directly proportional to the absorbance of the light.
  • A =  \varepsilon  C L
  • A =  6440 × 10⁻⁵ × 1
  • A = 6.44 × 10⁻²

Hence, absorbance was observed at 340 nm, A = 6.44 × 10⁻².

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