Extosd Given that sim 3A = cos (A-26)
Since sin 3A = cos (90° -3A)
From @ and @
cos (90°-3 A) = cos(A-26°/90° +26 = A + 3A
90° - 3A = A26
A = 290. is it my way of giving this solution is correct for cbse board exams
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yeah mate it is correct
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