extreme points of z=xy subjects to the condition x+y=1 are
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Answer:That can’t be a necessary condition because it is not necessary that the function be differentiable.
However, using the method of Lagrange multipliers, if the function H(x,y,z)=F(x,y,z)+λG(x,y,z) is differentiable then you can solve ∂F∂x+λ∂G∂x=0 , i.e. Fx=−λGx ,
∂F∂y+λ∂G∂y=0 , i.e. Fy=−λGy ,
∂F∂z+λ∂G∂z=0 , i.e. Fz=−λGz ,
together with G(x,y,z)=0 .
If you eliminate λ between the first two equations you should get your condition (which is clearly not sufficient as you have not used two of the equations).
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Step-by-step explanation:
the correct answer is [1/2,1/2,1/4]
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