Question

Eya !

#Physics

If the density of ice be 0.91 g/cc , then what will be the volume of ice when volume of water is
$1000 \: cm {}^{3}$
#ProperExplanationNeeded !!​

Answer 1

refer to attachment ok .....

Answer 2

Density of Ice = 0.91 g/cc

Volume of Water = 1000 cm^3

Density of water = 1g/cc

Mass = Density × Volume

So , Volume of ice × Density of Ice = Volume of Water × Density of Water.

=> Volume of ice × 0.91 = 1000×1

=> Volume of ice ×0.91 = 1000×100cm^3

=> Volume of ice = 100000cm^3/0.91g/cc

=>1098.9 cm^3

When estimated gives a value of 1099cm^3 .

Answer -> Volume of ice is 1099 cm^3