Math, asked by kanndsouza, 11 months ago

ez question answer plz

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Answers

Answered by manojtivar
1

Answer:

18 km/h is decrease in speed of car travelling in time 8 hr compare to time 6hr. And time at 90 km/hr speed will be 4. 8hr.

Step-by-step explanation:

Data

V1 = 72 km/hr

t1 = 6 hrs.

For distance d =

Now, as car covers 72 km in 1 hr so how, for 6 hrs it will become 72 × 6 = 432 km so d = 432 km.

Now, t2 = 8 hrs

for V2 = speed at same distance in 8 hrs = d/t2

V2 = 432/8

V2 = 54 km/hr

Now, V = V1-V2

V = 72 - 54

V = 18 km/hr is decrease in speed at same distance travelled in 8 hr.

Now, V3 = 90 km/hr

t3 =?

V3= d/t3

t3 = d/V3

t3 = 432/90

t3 = 4. 8 hr

Answered by Arnavisboss
0

Answer:

18 km/h is decrease in speed of car travelling in time 8 hr compare to time 6hr. And time at 90 km/hr speed will be 4. 8hr.

Step-by-step explanation:

Data

V1 = 72 km/hr

t1 = 6 hrs.

For distance d =

Now, as car covers 72 km in 1 hr so how, for 6 hrs it will become 72 × 6 = 432 km so d = 432 km.

Now, t2 = 8 hrs

for V2 = speed at same distance in 8 hrs = d/t2

V2 = 432/8

V2 = 54 km/hr

Now, V = V1-V2

V = 72 - 54

V = 18 km/hr is decrease in speed at same distance travelled in 8 hr.

Now, V3 = 90 km/hr

t3 =?

V3= d/t3

t3 = d/V3

t3 = 432/90

t3 = 4. 8 hr

Step-by-step explanation:

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