Question

f/02. Calculate the total number of electron
present in a drop of water. (Volunge of each
drop of water is 0.05 ml).​

Answer 1

Answer:

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Explanation:

Mass of water =0.05×1 = 0.05 gm

In 1 mole of water = 18 gm

In 0.05 gm of water =  

0.05 \18

  = 0.0027 mole

In 0.05 gm number of molecule = 0.0027×6.022×10  ^23

 

                                                     = 1.66×10  ^21

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