Question

f: 1-5, 9) - The function of IR is defined as | 6x + 1 -53 x 2 f (x) = 5x2 = 1; If 2 sx <6 is defined, see (3x - 4 -6 - 59 (1) / (- 3) + (2) (n) / (7) - ((1) (H) 2 / (4) + / {s) (iv) / {- 2) -10 TO + r - 2) ?​

Answer 1

f(x) = 6x + 1 ; x = {-5,-4,-3,-2,-1,0,1} f(x) = 5x2 – 1 ; x = {2, 3, 4, 5} f(x) = 3x – 4 ; x = {6, 7, 8, 9} (i) f(-3) + f(2) f(x) = 6x + 1