Question

f 10g H2 is allowed to react with 64g of O2 what weight of H₂0 will form? And which reactant will be left?​

Answer 1

Answer:

Explanation:

We know that the reaction between O₂ and H₂ is:

= 2H₂ + O₂ = 2H₂O

Number of moles of O₂=  $\frac{64}{32}$ = 2

Number of moles of H₂ = $\frac{10}{2}$ = 5

Now, 2 moles of H₂ react with one mole of O₂

So, 2 moles of O₂ react with 4 moles of H₂

i.e., 64g of oxygen reacts with 8g of hydrogen, leaving 4 moles of water. The weight of 4 moles of water is: 4 x 18 = 72g

Since only 8 moles of hydrogen is reacting, 2g of hydrogen is the reactant that is left

please mark me brainliest