Question

f(2/3)=3(2/3)cube+(2/3)square-20(2/3)+12
​

Answer 1

Answer:

(2/3)=3(2/3)cube+(2/3)square-20(2/3)+12

Answer 2

Answer:

Mark as brilliant please rank ka liya

Step-by-step explanation:

The given function is continuous at x=2.

Therefore,

lim

x→2

f(x)=lim

x→2

+

f(x)=f(2)

lim

x→2

=f(2)

Now, consider lim

x→2

f(x)=lim

x→2

(x−2)

2

x

3

+x

2

−16x+20

=lim

x→2

(x−2)

2

(x+5)(x−2)

2

=lim

x→2

(x+5)=7

Therefore,

7=f(2)=k

Hence, the required value of k is 7.