Question

F-2
The sum of the ages of father and a son is 45 years. 5 years ago of the product of their ages was 4
times the father's age at that time. Find their present ages.​

Answer 1

Answer:

Step-by-step explanation:

Let the father's age be x

Let the son's age be y

x + y = 45

y - 5 = 4(x - 5)

y = 4x + 20 - 5

= 4x + 15

x + (4x + 15) = 45

5x + 15 = 45

5x = 30

x = 6

y = 45 - 6 = 39

Therefore son's present age is 6 and father's present age is 39