Question

F=2yi+3x^2j calculate the work done if the particle is displaced from (1,2)to (3,9)

Answer 1

Hey friend here is the solution for this question.....

$workdone = change \: in \: potential \: energy$

potential energy at point (1,2)

$= f.s \\ = (2yi + 3 {x}^{2} j).(1i + 2j) \\ = 2y + 6 {x}^{2}$

potential energy at point (3,9)

$= f.s \\ = (2yi + 3 {x}^{2}j).(3i + 9j) \\ = 6y + 27 {x}^{2}$

so....

$workdone = (6y + 27 {x}^{2}) - (2y + 6 {x}^{2})$

$= 4y + 21 {x}^{2}$

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