Question

f 32y5 is a multiple of 3, where y is a digit then the value of y is (a)0 (b) 1 (c) 2 (d) none of these *

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

If 32y5 is a multiple of 3 , the sum of its digit should be divisible by 3.

Now, when we keep y = 2,

= 3+2+2+5

= 12

Which is divisible by 3 .

Hence y = 2.

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