f. 38-2(5-8-3) = [2[7+(-3)*(-4)}]
Answers
Answered by
1
Explanation:
38-2(-6)=2[7+12]
38+12=2×19
50 is not equal 38
Answered by
16
Answer:
LHS = 38 - 2(5-8-3)
RHS = [ 2(7+(-3) × (-4) ]
38 - 2(5-8-3) = [ 2(7+(-3) × (-4) ]
38 - 2 ( 5 - 11 ) = [ 2(7) + (12) ]
38 - 2 ( -6 ) = [ 2 ( 7 + 12 ) ]
38 - 2 × -6 = [ 2 ( 19 ) ]
38 - ( - 12 ) = 38
38 + 12 = 38
50 = 38
Here it is not equal
LHS ≠ RHS
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