Question

F=3i+4j newton is applied on a body of mass 2 kg. Calculate the magenitude ams direction of the acceleration inthe body?

Answer 1

Force= mass× acceleration.

Magnitude of force here,

|3i+4j| = √(3^2 + 4^2)= √25= 5 unit.

We use the formula √(A^2 + B^2 +2ABcosø)

Let theta be 90°, given force is applied ON the body.

Therefore, 5=ma

5=2×a

acceleration=2.5