f [3x 8][1 4]-3[2 -7]=5[3 2y], then the . 3 7 value of x is
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3x8][
1
3
4
7
]−3[2−7]=5[32y]
[3x+2412x+56]−[6−21]=[1510y]
[3x+24−612x+56+21]=[1510y]
[3x+1812x+77]=[1510y]
On comparing the corresponding terms , we have
3x+18=15 and 12x+77=10y
3x=−3 and y=(12x+77)/10
x=−1 andy=(12(−1)+77)/10
y=65/10=6.5
Thus x=−1 and y=6.5
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