F= 3yi cap + 2 xj cap is applied on partical , which moves from x = 0 to x=2 on path y = x+2 , find work done
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Answer:
32 J
Explanation:
F = 3y i + 2x j
displacement along x axis = final - initial
= 2 i - 0i {x=0 to x = 2}
= 2 i
displacement along y axis = final - initial
= 4 j - 2j [y = x+2]
= 2 j
total displacement = 2 i + 2 j
Work done = F . s
= 3y i + 2x j . 2 i + 2 j
= 6y + 4x
= 6(4) +4(2) [ x = 2; y = 4 ]
= 24 + 8
= 32 J
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