Question

F=40i+10j acts on a body of mass 5kg if the body starts from rest its position vector at time t=10s.

Answer 1

Answer:

force → F F→ =(40 ^ i i^ + 10 ^ j j^)N acts on a body of mass 5 kg. If the body starts from rest, its position vector → r r→ at time t = 10 s, will be :

(1) (100 ^ i i^ + 400 ^ j j^)m

(2) (100 ^ i i^ + 100 ^ j j^)m

(3) (400 ^ i i^ + 100 ^ j j^)m

(4) (400 ^ i i^ + 400 ^ j j^)m

Explanation:

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