f. 5(3x – 4y)^2 – 20(2x - y)^2?
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Answer:
-35x²-40xy+40y²
Step-by-step explanation:
Q. 5(3x – 4y)² – 20(2x - y)² ?
5{(3x)²-2.(3x)(4y+(4y)²} - 20{(2x)²-2.(2x)y+ y²}
=5( 9x²-24xy+16y²) -20( 4x²-4xy+y²)
= 45x²-120xy+80y²-80x²+80xy-20y²
= -35x²-40xy+40y²
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